Answer to Question #294345 in Mechanical Engineering for Dennis

Question

A gear drive consists of two gears, A and B, and has a velocity ratio of 1.50. Gear A, the

smaller of the two gears, revolves at 126 rpm in the clockwise direction, and has 28 teeth.

If the gears have a module of 2 mm, determine:

i)

The number of teeth on Gear B.

ii)

The pitch (reference) diameters for the two gears.

iii) The addendum.

iv) The dedendum.

v)

The circular pitch.

vi) The tooth thickness.

vii) The speed of Gear B.

viii) The theoretical centre distance of the two gears.

Answer 1

i)

VR=T_B/T_A

T_B=VR*T_A=1.5*28

T_B=42

ii)

d_A=mT_A=2*28=56mm

d_B=mT_B=2*42=84mm

iii)

a=m=2mm

iv)

d=1,157*2=2.314mm

v)

p=$\pi$ m=$\pi*2=6.28mm$

vi)

$t=\frac{\pi m}{2}=\frac{\pi*2}{2}=3.14mm$

vii)

VR=$\frac{N_A}{N_B}$

$N_B=\frac{N_A}{VR}=\frac{126}{1.5}=84rpm$

viii)

$C=\frac{m(T_A+T_B)}{2}=\frac{2*(28+42)}{2}=70mm$