Answer to Question #293766 in Mechanical Engineering for Nnko

Question

3. A 150X 100 X 15 mm mild steel angle is to be welded to a mild steel plate by fillet

weld along the edge of 150mm leg. A tensile load of 200kN acts through the gravity

axis of the angle. Determine weld lengths if the centre of gravity is at distance of

50mm from end B as shown in the figure below. The allowable shear stress in weld

material is 73N/mm2�

Answer 1

Given static loading =200 kN = 300 $\times 10^3$ N ,here dimension is given as 200 $\times 150\times 10$ ,

permissible shear stress= 73 $\frac{kN}{mm^2}$ ,here a+b=200

s= size of weld = thickness= 10 ,we know that

for single weld

$200 \times 10 ^3=0.707 \times s \times l\times \tau$

on putting value we can get value of l

l= 303.09 mm

$l_a+ l_b=565.77$

now distance of centroidal axis from bottom angle

b=55.3 and a= 144.7 so

$l_a= \frac{l\times b}{a+b}$

$l_a=156.44$ and $l_b= 358.88$