Question #289343

If for a certain BCC crystal, the (110) plane has a separation of 1.181A and wavelength of 1.540A



Find the glance angle for the 1st line of the reflection.



B. Hence find the atomic radius

1
Expert's answer
2022-01-23T22:16:02-0500

Bragg's Law 

nλ=2dSinθn\lambda= 2dSin\theta

glance angle for the 1st line of the reflection.


θ=Sin1(1×1.5402×1.181)=40.690\theta = Sin^{-1}(\frac{1\times 1.540}{2\times 1.181}) =40.69^0


atomic radius

R=34a=341.181=0.511R = \frac{\sqrt3}{4}a= \frac{\sqrt3}{4}1.181 = 0.511


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