Draw a helical spring of circular wire and -in terms of load, dimensions, and material- express:
helical spring of circular wire
max. shear stress τmax=Ks8FDπd3\tau_{max}= K_s {\frac{8FD}{\pi d^3}}τmax=Ksπd38FD where Ks=1+12CK_s =1+\frac{1}{2C}Ks=1+2C1
axial deflection, δ=8FD3NGd4\delta= \frac{8FD^3N}{Gd^4}δ=Gd48FD3N
spring rate, K
length of spring wire. L
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