An automobile tire has a volume of 1000 cm³. It is inflated with carbon dioxide to pressure of 40 psig at 23°C.How many grams of carbon dioxide are contained in the tire?
pV = nRT
p = 40 psig = 2.7218 atm
V = 1000 cm3 = 1 L
T = 23°C = (23 + 273 K) = 296 K
n = pV/RT = (2.7218 atm) x (1 L) / (0.08206 L atm K-1 mol-1) x (296 K) = 0.112 mol
n = m/M
m = 0.112 mol x 44 g/mol = 4.93 g
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