Answer to Question #285792 in Mechanical Engineering for Tan

Question

A rigid vessel contains 6 kg of wet steam at 0.4 MPa with a quality of 75% until the steam

has a temperature of 300C. Determine the initial internal energy and the final pressure.

Answer 1

at wet steam at 0.4 MPa with a quality of 75% 

 Final Temperature T₂= 460⁰C from steam table

Internal Energy

$\delta E= m\times C_p dt =6\times 1\times (733-573) =960\frac{kJ}{kg}$

$P2 =P1\times 0.75 =0.4\times 0.75 = 0.3 Mpa$

as we konw,

$P_1T_1=P_2T_2$

$p_2= \frac{0.4\times573}{733}=0.3Mpa$