The engine mechanism shown in Fig. 5 has crank OB = 50 mm and length of connecting rod
AB= 225 mm. The centre of gravity of the rod is at G which is 75 mm from B. The engine
speed is 200 r.p.m.
Fig. 5
For the position shown, in which OB is turned 45° from OA, Find 1. the velocity of G and the
angular velocity of AB, and 2. the acceleration of G and angular acceleration of AB.
N=200rpm
OB=50mm=0.05m
AB=225mm=0.225m
GB=75mm=0.075m
From velocity diagram,
Hence,
Plot in velocity diagram to find VOG
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