Answer to Question #278771 in Mechanical Engineering for Joe melwin Raja

Question

A single cylinder single acting four stroke cycle gas engine develops 22 kw at 300 rpm the fly wheel mass is 100kg hoop stress developed is 5 Mpa density of material of rim of fly wheel is 800Kg/m 3.The speed variation on the either side is 1% of mean speed. Determine the ratio of work done during expansion and compression strokes work done in suction and exhaust stroke is negligible.

Answer 1

$T_{mean}=\frac{P*6}{2π*N}$

$=\frac{22*10^3*60}{2*π*300}$

=700.28Nm

Work done per cycle=$T_{mean}*\theta$

=700.28*4π

=2200

$Required\ ratio=\frac{W_e}{W_c}$

$=\frac{6418.38}{2381.62}$

=2.69