Answer to Question #270908 in Mechanical Engineering for Drixie

Question

The pressure on 142 l/min of air is boosted reversibly from 2,068.44 kPaa to 6,205.32 kPaa while the temperature remains constant at 24° C ∆U= 0. a) find the integral of pdV and - integral of Vdp. (b) for a nonflow process, find W,Q,∆H, and ∆S. (c) for steady flow process during which ∆K= 5 kJ/min and ∆P=0, find the integral of pdV, - integral of Vdp, W, ∆E, ∆H, Q, and ∆S

Answer 1

Diagrams with the table for answer is given below: