Question

A 150mm-diameter hollow sphere weighing 300 N is attached to a solid concrete block weighing 5.3 kN. If the concrete has a specific weight of 27.7 kN/m3, what will be the state of the two

Answer 1

Specific weight = mass/volume

volume = mass/specific weight

volume of concrete block = 5.3/27.7 = 0.19 m³

radius of hollow sphere = 150/2 = 75 mm = 75 × 10^-3 m³

Volume of the sphere = 4/3 πr³ = $4/3 × 3.142 × 75 ×10^{-3} = 0.314\ m³$