Question #268935

 A 150mm-diameter hollow sphere weighing 300 N is attached to a solid concrete block weighing 5.3 kN. If the concrete has a specific weight of 27.7 kN/m3, what will be the state of the two objects together in water?      


1
Expert's answer
2021-11-22T14:05:02-0500

FB=ρgV=10009.8(43.140.0753/3)=17.3 (N)300 (N)F_B=\rho gV=1000\cdot9.8\cdot(4\cdot3.14\cdot 0.075^3/3)=17.3\ (N)\ll300\ (N)


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The two objects together will drown under the action of gravity.




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