A wedge belt is required to transmit 18.5kw from an electric motor running at 1455rpm to a uniformly loaded conveyor running at 400rpm. The desired center distance is 1.4m select a suitable belt and determine the diameter of the pulleys
P=18.5kW
"\\eta_1=1455rpm"
"\\eta_2=400rpm"
C=1.4m
"Speed\\ ratio=\\frac{1455}{400}=3.6375"
From the standard tables at speed ratio<10; service factor=1.1
Hence design power =18.5*1.1=20.35kW
From the standard tables, for P=20.35kW
The centre distance=112mm and suitable belt is flat belt
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