Answer to Question #263762 in Mechanical Engineering for Suraj

Question

a compound gear train in which, wheel A is fixed to the driving shaft, B-C are

compounded , D is idle, and E is fixed on the driven shaft. If gear A rotates at 1000 r.p.m find

the speed and direction of E. driven shaft.

Answer 1

Drive shaft rotates at 1000rpm=Gear A

x+y=1000 this will be equation (i)

Gear E is fixed , $y+x*(\frac{T_AT_D}{T_CT_B})=0$

Taking T_A=30, T_B=32, T_C=30, T_D=22

$y+x*(\frac{30*22}{20*32})=0$

$y+x(\frac{66}{64})=0\implies y=-x(\frac{66}{64})$

Use in equation (i)

$x+(-x(\frac{66}{64}))=1000$

$\frac{64x-66x}{64}=1000$

-2x=64000

x=-32000

The required speed, y$=-x(\frac{66}{64})$

$=-(-32000)(\frac{66}{64})$

=33000rpm in the clockwise direction since it's positive.