Answer to Question #262514 in Mechanical Engineering for Angel

Question

A journal runs in a bearing diameter , 25mm , and length 100 mm at 25 . The clearance gap is 0.8 mm . The lubricant used has a dynamic viscosity of 80 CP . The bearing must carry a side load of 800N . Calculate the values of:

a) the friction force

b) coefficient of friction

Note : 1cP = 1mPa - s

Answer 1

(A)

The friction force will be:

F=ma

=$800\times 25$

$20,000= 20KN$

(B)

Coefficient of friction is defined as the ratio of the force required to move tow sliding surfaces over each other, and the force holding them together.

$20,000/800=25$

answer will be $25$