Answer to Question #261702 in Mechanical Engineering for Nuzra

Question

A disk 254 mm in diameter accelerates uniformly from a speed of 1000 r/min to 2000

r/min in 20 s. Find (a) the angular acceleration in radians per second squared and (b) the

revolutions of the disk during the 20-s interval.

Answer 1

(a)

$\alpha=\frac{\omega_2-\omega_1}{t}=0.83\text{ r/s}^2.$

(b)

$N=\frac{\omega_2^2-\omega_1^2}{2\alpha}=502\text{ revolutions}$