A Fahrenheit and a centigrade thermometer are both immersed in a fluid. The Fahrenheit numerical reading is twice that of the centigrade reading. What is the temperature of the fluid in Rankine and Kelvin scale?
Say, the temp. is T = t deg C
Therefore, F = 2t deg F
Now, "F = \\frac{9}{5}C + 32"
"2t = \\frac{9t}{5}+32"
10t = 9t + 160
Or t = 160 deg C = 160 + 273 = 433 deg. K
Hence T = 320 deg. F
deg Rankine = (deg. C + 273.15)*1.8 = (160 + 273.15)*1.8 = 779.67 deg R
Final Answer: Temp. T = 160 deg C, 320 deg. F, 779.67 deg. R
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