The gage pressure of a gas inside a tank is 25kPa. Determine the vertical height, in meters, of liquid within a manometer attached to the system if the fluid at room temperature is (a) water, (b)mercury (ρ=13,600kg/m3), and (c) an oil with a specific gravity of 0.88 and g=9.75 m/s2
pressure: 25kPa ; NL = 30.00m ; E = 2.0x106kg/cm2 ; G=0.88 ; W = 0.03kg
"\\text Try\\space Pn = 5.78"
5.1683 = "\\frac{2.12}{(5.1683-5)^{1\/2}}"
it very close to the answer.
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