A 100-mm radius cylinder filled with water is fitted with a piston of negligible weight. A force F is applied to the piston. The manometer attached is filled with mercury (SG = 13.57) and is displaced as shown. Determine the force F.
pressure p=ρgh=13.57××9.81×1=1806.46Nm2p= \rho gh=13.57\times\times9.81\times1=1806.46\frac{N}{m^2}p=ρgh=13.57××9.81×1=1806.46m2N
forceF=p×A=1806.546×π40.12=14.18NF = p\times A =1806.546\times\frac{\pi}{4}0.1^2 =14.18NF=p×A=1806.546×4π0.12=14.18N
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments