Question #257159
20 samples, each the size of 7. The center line of a three sigma pair of X bar and R chart, used for monitoring the process, is 55.9 & 12.6, respectively. Assume the process is IN statistical CONTROL. What is the Average Run Length to detect a shift of the process mean to 60. std remains the SAME
1
Expert's answer
2021-10-27T07:02:55-0400

X is normally distributed

xˉ=μ=55.9\bar x=\mu=55.9

σ=ϵ=12.6\sigma=\epsilon=12.6

n=7

μxˉ=55.9\mu_{\bar{x}}=55.9

σxˉ=σn=12.67=4.7624\sigma_{\bar{x}}=\frac{\sigma}{\sqrt{n}}=\frac{12.6}{\sqrt{7}}=4.7624

P(20<z<60)=P(2055.94.7624<xμxˉσxˉ<6055.94.7624)P(20<z<60)=P(\frac{20-55.9}{4.7624}<\frac{x-\mu_{\bar{x}}}{\sigma_{\bar{x}}}<\frac{60-55.9}{4.7624})

=P(7.5382<z<0.8609)=P(-7.5382<z<0.8609)

=P(z<0.8609)P(z<7.5382)=P(z<0.8609)-P(z<-7.5382)

=1.613=1.613


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