Answer to Question #256732 in Mechanical Engineering for asasasa

Question #256732

The bars AB and AC are joined by a pin at A and a horizontal cable. The vertical cable carrying the 200-kg mass is attached to the pin at A. Determine the tension in the horizontal cable. Neglect the weights of the bars.


1
Expert's answer
2021-11-01T08:51:53-0400



FACSin 60=FABSin 30

"F_{AB}=\\sqrt3F_{AC}"

"F_{AC}Cos 60+F_{AB}Cos 30+Mg=0"

"\\frac{F_{AC}}{2}+\\sqrt3F_{AC}\\frac{\\sqrt3}{2}+200*9.81=0"

"F_{AC}=-981N"

"F_{AC}Cos30+T=0"

"T=-F_{AC}Cos30"

"=-(-981)Cos30"

"=849.57N"


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS