Question #246341

In a non flow process there is heat transfer loss of 1055kJ and internal energy increase of 210kJ determine the work transfer and state whether the process is expansion or compression

Expert's answer

Q=1055kJU=210kJW= ?Q =-1055kJ\\ ∆U = 210kJ\\ W =\ ?


U=QW210=1055WW=1265 kJ∆U = Q- W\\ 210= -1055-W\\ W = 1265\ kJ


Since work done is positive, there is an increase in volume.


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