Let positive y-axis be pointing up. Then
v(t)=v0−gt=−gt,v0=0
y(t)=y0+v0t−2gt2=y0−2gt2,v0=0,y0=100 m (a)
v(4)=−9.81 m/s2(4 s)=−39.24 m/s
(b)
y(4)=100 m−29.81 m/s2(4 s)2=21.52 m (c)
P=mgy
P∣t=0=10 kg(9.81 m/s2)(100 m)=9810 J
P∣t=4=10 kg(9.81 m/s2)(21.52 m)=2111.112 J
K=2mv2
K∣t=0=0
K∣t=4=210 kg(−39.24 m/s)2=7698.888 J (d)
E=P+K=const
E=9810 J+0 J=9810 J
=2111.112 J+7698.888 JThe total mechanical energy of the ball is 9810 J and is conserved during the motion.
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