Question #241839

A weight of 20kg acts tangentially at a radius of 650 mm and causes a pulley to accelerate uniformly from 35 rev/min to 120 rev/min in 20 seconds. Calculate the work done and the average power required to cause this acceleration.


Clearly show the following values

wi=?

wf=?

θ=?

Torque=?

W=?

Pave=?



1
Expert's answer
2021-09-25T11:38:59-0400

W=20kgW=20kg

t=20 sec


actual air temprature Ta =25°25\degree

from the data

hα0.8Vh\alpha 0.8 V

h=k(0.8V)h=k(0.8V)

in the thermocouple read the radiation from the wall is proportional to ΔT\Delta T

qradiationq_{radiation}

qradiation=C(ΔT)q_{radiation} = C(\Delta T)

=C(Tb-Tw)

consider energy balance

qconductionq_{conduction}

hΔT=CΔ(TbTw)h\Delta T=C \Delta (Tb -Tw)

k(0.8V)ΔT=C(TbTw)k(0.8V)\Delta T = C (Tb - Tw)

from equation 1

0.8(5)k(2550)=C(50Tw)0.8 (5) k (25 - 50) = C (50 - Tw)

0.8(10)k(2540)=C(40Tw)0.8 (10) k (25 - 40) = C (40 - Tw)

2/3=(0.8)(5)k(25)/(0.8)(10)k(15)=C(50Tw)/C(40Tw)2/3 =(0.8) (5) k (-25) /(0.8)(10) k(15) = C (50 - Tw) / C ( 40 - Tw )

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