Question #241334

When a certain perfect gas is heated at constant pressure fr 15 degree C to 95 degree C, the heat required is 1136KJ/Kg.When the same gas is heated at constant volume between the same temperatures the heat required is 808KJ/Kg. Calculate the Cp, Cv, R and molar mass of the gas.


1
Expert's answer
2021-09-24T02:15:52-0400

T1=15°T 1 ​ =15°

T2=95°T 2 ​ =95°


ΔQ1=1136kg/kJΔQ _1 ​ =1136 kg/ kJ

ΔQ2=808kg/kJΔQ _2 ​ =808 kg/ kJ ​


ΔQ1=cpΔTcp=ΔQ1/ΔT​​=1136000/80=14200J/kgKΔQ _1 ​ =c _p ​ ΔT→c _p ​ = ΔQ _1/ΔT ​ ​ = 1136000/80 ​ = 14200 J/kgK


ΔQ2=cvΔTcv=ΔQ1/ΔT​​=808000/80=10100J/kgKΔQ _2 ​ =c _v ​ ΔT→c _v ​ = ΔQ _1/ΔT ​ ​ = 808000/80 ​ = 10100 J/kgK

γ=cp/cv​​=14200/10100=1.4γ= ​ c _p/c_v ​ ​ = 14200/10100 ​ =1.4


Rm=cpcV=1420010100=4100J/kgKR _m ​ =c _p ​ −c _V ​ =14200−10100=4100 J/ kg⋅K ​

R=RmMM=R/Rm​​=8.31/4100=0.002kg/molR=R _m ​ ⋅M→M= R/R _m ​ ​ = 8.31/4100 ​ =0.002 kg/mol

The gas is hydrogen (H2)(H_2)


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