Question

5. A water pump delivers 130 dm3/minute (0.13 m3/min) drawing it in at 100 kPa and delivering it at 500 kPa. Assuming that only flow energy changes occur, calculate the power supplied to the pump. (860 W)

Answer 1

Solution;

Given;

Volume flow rate ,$v/s=0.13m^3/min$

Pressure;

$P_1=100kPa$

$P_2=500kPa$

Ignoring K.E and P.E

$Q+P=\Delta F.E/s$

In which P is power.

F.E is flow energy.

But Q=0

Hence;

$P=$ $\frac{0.13}{60}×(500-100)×10^3$

P=866.67W

Answer;

866.67W