A non-flow system receives 80 kJ of heat transfer and loses 20 kJ as work transfer. What is the change in the internal energy of the fluid?
By applying the first law of thermodynamics to the given non-flow system;
Q=∆U-W
Given;
W=20kJ
Q=80kJ
Q=∆U-W
Thus; ∆U=Q-W
=(80-20)kJ
=60kJ.
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