Answer to Question #232781 in Mechanical Engineering for jhy

Question

Find the equivalent spring constant of the system shown in figure below

Answer 1

In Series :

Equivalent spring constant : $\frac{1}{k_{eq}} = \frac{1}{k_1}+\frac{1}{k_2}$

In Parallel :

Equivalent spring constant : $k_{eq}=k_1+k_2$

Where $k_1$ and $k_2$ are spring constant