Question #231597

A refrigerator operates on the reversed Carnot cycle and uses water as the working

fluid. At the beginning of the isothermal expansion, the steam has an absolute

pressure of 1kPa and a quality of 7%; at the end of the isothermal expansion, the

steam is dry and saturated. At the end of heat rejection process the water is saturated

liquid. Firstly: Sketch the T‐s and P‐v diagrams for the cycle, and secondly: for one kg

of water, calculate: a) The steam pressure at beginning of the heat rejection process,

b) the net work per cycle, c) the COP of the cycle in two conditions: 1‐refrigeration

and 2‐heat pump


1
Expert's answer
2021-09-01T03:04:20-0400

The performance of refrigerators and heat pumps is expressed in terms of coefficient of performance (COP):

COPR=QLWinCOP_R = \frac{Q_L}{W_{in}}


COPHP=QHWinCOP_{HP} = \frac{Q_H}{W_{in}}

Reversed Carnot Cycle:


An internally, reversible, constant pressure heat rejection

QH=h2h3Q_H = h_2 − h_3 ...h3=h4h_3 =h4

An internally, reversible, constant pressure heat interaction

QL=h1h4Q_L = h_1− h_4


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