Question #229141

A thick cylinder of internal and external radii 300 mm and 500 mm respectively is subjected to a gradually increasing internal pressure P. Determine the value of P when:

(a) the material of the cylinder first commences to yield;

(b) yielding has progressed to mid-depth of the cylinder wall;

(c) the cylinder material suffers complete “collapse”.

Take uY = 600 MN/m’.


1
Expert's answer
2021-08-27T02:07:20-0400

By Lame's theorem hoop system,

When the material starts yielding,

δθ=(ρi×ri)(r02ri2)((ro2)(r2)+1)\delta_{\theta} =\dfrac{ (\rho_{i}×r_{i})}{(r_{0} ^ 2 - r_{i} ^ 2) }(\dfrac{(r_{o} ^ 2)}{(r ^ 2)} + 1)


ri = internal radius = 300mm = 0.3m

ro = external radius = 500mm = 0.5m

where, r = mean radius = (300+500)/2(300+500)/2 = 400mm

600=ρi×0.30.520.32×(0.52)(0.42)+1600 =\dfrac{ \rho_{i}×0.3}{0.5^ 2 -0.3 ^ 2}× \dfrac{(0.5^ 2)}{(0.4^ 2)} + 1


ρi=124.9 Pa\rho_i =124.9\ Pa

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