Determine ho and Side flow rate and the power loss using the following
given parameters: Temperature = 62 C, N = 40 rev/s, W = 2 kN (bearing
load), r = 20 mm, c = 0.04mm, and l = 3.2 cm
velocity
"V = \\frac{2\\pi N}{60} =\\frac{2\\pi 40}{60} = 4.19 \\frac{m}{sec}"
flow rate
"Q = \\frac{\\pi}{4}D^2 V = \\frac{\\pi}{4}\\times 0.04^2 \\times4.19 =0.0053 \\frac{m^3}{sec}"
Darcy’s equation to calculate the loss
"h_L=f\\times \\frac{L}{D}\\times \\frac{v^2}{2g}\n\\,."
"h_L=0.00004\\times \\frac{0.032}{0.04}\\times \\frac{4.19^2}{2\\times9.81} = 2.86\\times10^-5 m =0.0286mm\n\\,."
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