Question #224633

A 14 m long truck is driven alongside a 500 m long train with the same velocity of

25 m/s. The front of the truck is 7 m behind the rear of the train. At a certain instant, the

truck stars accelerating at 0,08 m/s2, while the train starts decelerating at 0,4 m/s2. How

long will it take before the rear of the truck passes the front of the train and what distance

would the truck have covered in this time?


Expert's answer

1) After t sec the truck passes the front of the train

S=ut+12at2S = ut+\frac{1}{2}at^2

Initial velocity u=0u=0

493=0+12×0.08t2=111493 = 0+\frac {1}{2}\times 0.08 t^2 = 111  sec

2) Let the distance be d meters

When they met

60+d=25×11112×0.4×111260+d= 25\times111-\frac{1}{2} \times0.4\times111^2

d=310.860=250.8d = 310.8-60=250.8 m




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