Question #224633

A 14 m long truck is driven alongside a 500 m long train with the same velocity of

25 m/s. The front of the truck is 7 m behind the rear of the train. At a certain instant, the

truck stars accelerating at 0,08 m/s2, while the train starts decelerating at 0,4 m/s2. How

long will it take before the rear of the truck passes the front of the train and what distance

would the truck have covered in this time?


1
Expert's answer
2021-08-16T02:33:01-0400

1) After t sec the truck passes the front of the train

S=ut+12at2S = ut+\frac{1}{2}at^2

Initial velocity u=0u=0

493=0+12×0.08t2=111493 = 0+\frac {1}{2}\times 0.08 t^2 = 111  sec

2) Let the distance be d meters

When they met

60+d=25×11112×0.4×111260+d= 25\times111-\frac{1}{2} \times0.4\times111^2

d=310.860=250.8d = 310.8-60=250.8 m




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