A 3-phase, 4 pair of poles, 400kW, 400V, 60Hz induction motor is 780 rpm full-load speed.
Determine the frequency of the rotor current under full load condition
fr=sf
ns="\\frac{120f}{p}=\\frac{120*60}{8}=900rpm"
s="\\frac{n_s-n}{n_s}=\\frac{900-780}{900}=0.1333"
fr=sf
=0.1333*60
=7.998 Hz
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