Answer to Question #221984 in Mechanical Engineering for Omelatum

Question #221984
A 1 kg steamActivity 2 0 water mixture at 1.0 MPa is contained in an inflexible tank. Heat is added until the pressure rises to 3.5 MPa and 400 C. Determine the heat added
1
Expert's answer
2021-08-04T02:52:28-0400

m=1kgP1=1.0 MPaP2=3.5 MPaU1=2401.41kJkgU2=2926.4kJkgT=400°Cm = 1 kg\\ P_1 = 1.0\ MPa\\ P_2 = 3.5\ MPa\\ U_1 = 2401.41\frac{ kJ} {kg}\\ U_2= 2926.4 \frac{ kJ} {kg}\\ T = 400°C
Heat transferred = m(U2U1)=m(U_2-U_1) =1(2926.42401.41)=524.991(2926.4-2401.41) = 524.99=524.99kJ= 524.99 kJ

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