Calculate the forces in members BE and BD of the loaded truss. The forces are positive if in tension, negative if in compression. Assume F = 4.4 kN, a = 2.3 m, b = 3 m, c = 2 m, and d = 2 m.
In order to find BE we will resolve force at point E
"\\sum F_y=0\\\\\n F_{BE}=0"
Force in member BE = 0
In order to find force in BD, we can resolve force along a vertical direction at point B
"\\sum F_y=0\\\\\n F_{BE}+F_{AB} cos \\theta+F_{BD} cos \\theta=0\\\\\nSince \\space F_{BE} =0\\\\\nF_{AB} cos \\theta = -F_{BD} cos \\theta \\\\\nF_{AB}=-F_{BD}-------(1)"
Now we need to find FAB
At point A resolving along the vertical direction
"F= F_{AB}sin \\theta\\\\\nF= F_{AB} \\frac{3}{\\sqrt{13}}\\\\ \nF_{AB}= \\frac{\\sqrt{13}}{3}(4.4)\\\\ \nF= 5.28814kN (Tension)"
Substituting in equation 1
"F_{AB}= -F_{BD}\\\\\n5.28814= -F_{BD}\\\\\nF_{BD}=-5.28814(Compression)"
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