At 2 MPa
"v_f= 0.001177m^3\/kg; v_g=0.099587 m^3\/kg\\\\\nu_f=906.12kJ\/kg ; u_{fg}=1693 kJ\/kg\\\\\nv_1 = v_f x_1(v_g-v_f)= 0.001177+0.75(0.099587-0.00117)=0.07498 m^3\/kg\\\\"
3.2.1
3.2.2
"m= \\frac{V}{v_1}= \\frac{0.8}{0.07498}=10.67 kg\\\\\nm_s = 0.75*10.67=8.0025 kg\\\\\nm_l=0.25*10.67 =2.6675 kg"
3.2.3
"u_1=906.12+0.75*1693=2175.87 kJ\/kg\\\\\nU_1=mu_1=2*2175.87 = 4351.74 kJ"
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