Question #219593

If the distance between the sun and the earth was the half of what it is L = 0.5 × 1.496 ×1011 m, what would the solar constant be? The sun is a nearly spherical body that has a diameter of D = 1.393 ×109 m and the effective surface temperature of the sun is Tsun = 5778 K. 𝜎 = 5.67 x10-8 W/m2K 4 .


1
Expert's answer
2021-07-25T22:37:01-0400

Energy Emitted from sun E=σT4E=\sigma T^4


E=5.67×108×57784=63.1965×106WE=5.67 \times 10^{-8}\times 5778^{4} =63.1965 \times 10^6 W


E = total energy intercepted (technically, energy flux = energy per unit time, in watts)


KS = solar insolation ("solar constant")


R_E = Radius of Sun =D2=75.91m= \frac{D}{2} =75.91 m


E=KS×πRE2E = K_S\times \pi{ R_E}^{2}


Ks=63.1965×106π×75.912=3524.1wattm2K_s = \frac{63.1965\times10^6}{\pi\times 75.91^2} =3524.1 \frac {watt}{m^2}



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