d=758mmd = 758 mmd=758mm
t=18mmt = 18 mmt=18mm
p=7Nmmp = 7 \frac{N}{mm}p=7mmN
E=2.1×105NmmE = 2.1 \times 10^ 5 \frac{N}{mm}E=2.1×105mmN
μ=0.25\mu = 0.25μ=0.25
Change in diameter (δd)(\delta d)(δd) :
δd=pd24tE[1−1m]\delta d = \frac{pd^2}{4tE}[1-\frac{1}{m}]δd=4tEpd2[1−m1]
δd=7×75824×18×2.1×105[1−0.25]=0.1995mm\delta d = \frac{7\times 758^2}{4\times 18\times 2.1\times 10^5}[1-0.25]=0.1995 mmδd=4×18×2.1×1057×7582[1−0.25]=0.1995mm
Change in volume (δv)
ev=3×δdde_v = 3\times \frac{\delta d}{d}ev=3×dδd
V=π6×d3=π6×7582=300841mm3V = \frac{\pi}{6}\times d^3 = \frac{\pi}{6}\times 758^2 =300841mm^3V=6π×d3=6π×7582=300841mm3
δvv=3×δdd\frac{\delta v}{v} = 3\times \frac{\delta d}{d}vδv=3×dδd
δd=3×300814×0.1995758=237.51mm3\delta d =3 \times 300814 \times \frac{0.1995}{758} =237.51 mm^3δd=3×300814×7580.1995=237.51mm3
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments