One spring I placed inside the other and compressed between a pair of parallel plates until the distance between the two plates is 40mm calculate the force applied to the spring assembly
Force applied to the spring assembly
F=12QEF =\frac{1}{2}QEF=21QE
V = 0.8
Q=CV=1×0.8=0.8Q = CV =1 \times 0.8 = 0.8Q=CV=1×0.8=0.8
E=Vd=0.80.04=20E = \frac{V}{d} =\frac{0.8}{0.04}= 20E=dV=0.040.8=20
F=12QE=12×20×0.8=8NF =\frac{1}{2}QE = \frac {1}{2}\times20\times0.8 = 8NF=21QE=21×20×0.8=8N
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