Question

A 2 kg nitrogen gaseous in a piston-cylinder receives heat at a constant pressure of 350 kPaa. The gas temperature increases from 320

Answer 1

heat at a constant pressure

$Q = mCp \triangle t$

$Q =2 \times 1.23 \times 320 = 787.2 \frac{kJ}{kg}$ ...$C_p = 1.23$ for $N_2$

Work done :

$W = Q + \triangle U = 787.2+320 = 1107.2 kW$