heat at a constant pressure
"Q = mCp \\triangle t"
"Q =2 \\times 1.23 \\times 320 = 787.2 \\frac{kJ}{kg}" ..."C_p = 1.23" for "N_2"
Work done :
"W = Q + \\triangle U = 787.2+320 = 1107.2 kW"
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