Given :-
Mass Flow rate (m)= 0.2 kg/s
Intial State(1)
P1= 99 Kpa
v1= 0.81 m3/Kg
Final State(2)
P2= 600 Kpa
In a Isothermal process magnitude of work is equal to heat loss or gain
W = mP1v ln(P1/P2)
W = 0.2* 99000*.81 *ln(99/600)
W = - 28897.7 J
HEAT LOSS = 288897.5 j
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