From the top of a building 75m, a bullet is fired at an angle of 45° above the horizontal with an initial velocity of 270 m/s. Find the time until it hits the ground.
The initial vertical velocity is downward and the acceleration due to gravity will increase this downward velocity
"V_i = 270 cos 45^0 = 190.91 \\frac{m}{sec}"
"d=v_it+\\frac{1}{2}at^2"
"75 =190.91\\times t+\\frac{1}{2}\\times 9.8\\times t^2"
Changing to standard quadratic form yields
"4.9 t^2 + 190.91t-75 = 0"
This equation can be solved with the quadratic Equation:
t = 0.39 sec
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