Question

A trench mortar fires a projectile at an angle of 53° above the horizontal with a muzzle velocity of 60 m/s. A tank is advancing directly towards the mortar on level ground at a speed of 3 m/s. What should be the distance from the mortar to tank at the instant the mortar is fired in order to score a hit?

Answer 1

R = $\dfrac{u²\sin2\theta}{g}=\dfrac{60²\sin106°}{10}= 346m$

$T = \dfrac{2u\sin\theta}{g} = \dfrac{2×60\sin53°}{10}= 9.6s$

$s= ut = 3× 9.6 = 28.8m$

$\therefore$ The distance from the mortar to tank at the instant the mortar is fired is (28.8m + 9.6m = ) 38.4m.