Answer to Question #206820 in Mechanical Engineering for Rodel

Question

. A ball is thrown horizontally from the roof of a building 45m tall and lands 24m from the base. What was the balls initial speed?

Answer 1

Let U be the initial horizontal velocity of ball.

Since the horizontal velocity of the ball remains constant.

$U=\frac{Horizontal distance}{Time}$

The time taken by the ball to fall from height of H=45 m is given by kinematical equation in vertical direction.

$H=\frac{1}{2}×g×t^2\\t=\sqrt{\frac{2×H}{g}}\\t=\sqrt{\frac{2×45}{9.8}}=3.03 sec$

Hence, U=24/3.03=7.92m/s

Answer: The initial velocity is 7.92 m/s