Answer to Question #206818 in Mechanical Engineering for Rodel

Question

A ball is thrown at angle of 30° above the horizontal with a speed of 10 m/s. After 0.5 sec, find the horizontal component of its velocity.

Answer 1

the horizontal component of its velocity $v _x = vcosθ = 10 \times cos 30 = 8.66 \frac{m}{sec}$

after 5 sec

Velocity $v = v_x + at = 8.66 + 1\times 0.5 = 9.16 \frac{m}{sec}$