Answer to Question #204866 in Mechanical Engineering for jesabell briones

Question

Suppose you have a 1020 steel plate in axial loading, with an axial F of 30000 lbf.  The plate is 1⁄4” thick, 2” high, and 6” length. The hole is in the center of the  plate, and is 1/4“ in diameter. The plate is at room temperature, and the strain at  fracture is greater than εf > 0.1. If Sy = 80 ksi and Sut = 100 ksi, calculate the highest  stress in the plate.

Answer 1

There is no need for a stress concentration factor as this material is ductilenote that ε

f > 0.1

The highest stress will be at the lowest cross-sectional area, which occurs at

the hole. Therefore

$\sigma= \frac{ F}{ (t)(h - d)} = \frac{30000lbf}{ (0.25in)(2in - 0.25in)} = 68,600psi = 68.6ksi$