A solid cylinder is to be 0.25 m in diameter. The base of axial length 25 mm is to be of metal which has a specific gravity of 7, and the remainder of material which has a specific gravity of 0.5. Find the maximum overall length of the cylinder so that it may float in water in stable equilibrium with its axis vertical.
Question is based on the solid cylinder . Diameter of cylinder, axial length and specific gravity of material are given in the question . Maximum overall length of cylinder has to be determine.
Diameter of cylinder (D) = 0.25 m
Specific gravity of metal (Gm) = 7
Specific gravity of fluid (G) = 0.5
For floating to happen "W=F_B \\implies G_M*A*H=G_{water}*A*l"
"0.5*H=l"
For stable equilibrium "M.G= \\frac{l_{min}}{V}=B.G"
So, "\\frac{\\frac{\\pi*254^4}{64}}{\\frac{\\pi}{4}*250^2*l}=l-0.5 \\implies \\frac{60.96}{l}=0.5l"
"l=0.044 m"
Comments
Leave a comment