Answer to Question #202708 in Mechanical Engineering for Lihle

Question #202708

Determine the minimum diameter to maintain stable conditions for a warming bouy. The centre of gravity is 750 mm above the base. It has a height of 2,75 m and a relative density of 0,55. It should float with its longitudinal axis in the vertical plane in seawater with a density of 1025kg/m^3.


1
Expert's answer
2021-06-07T05:49:53-0400

density of buoy = 0.55 × 1025kg/m³ = 563.75kg/m³

ρ=1025563.75=461.25kg/m³∆\rho = 1025 - 563.75 = 461.25kg/m³


Vup=(2.750.75)×π(d²4)=1.571d2V_{up}= (2.75 -0.75)× \pi (\dfrac{d²}4) =1.571 d^2

Vdown=(0.75)×π(d²4)=0.589d2V_{down}= (0.75)× \pi (\dfrac{d²}4) = 0.589 d^2


1.571d²0.589d²=10.982d2=1d²=10.9821.571d²- 0.589d² = 1\\ 0.982 d^2 =1\\ d² = \dfrac1{0.982}


d=10.982=1.009md = \sqrt{\dfrac{1}{0.982}} = 1.009m

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