Determine the minimum diameter to maintain stable conditions for a warming bouy. The centre of gravity is 750 mm above the base. It has a height of 2,75 m and a relative density of 0,55. It should float with its longitudinal axis in the vertical plane in seawater with a density of 1025kg/m^3.
density of buoy = 0.55 × 1025kg/m³ = 563.75kg/m³
"\u2206\\rho = 1025 - 563.75 = 461.25kg\/m\u00b3"
"V_{up}= (2.75 -0.75)\u00d7 \\pi (\\dfrac{d\u00b2}4) =1.571 d^2"
"V_{down}= (0.75)\u00d7 \\pi (\\dfrac{d\u00b2}4) =\n0.589 d^2"
"1.571d\u00b2- 0.589d\u00b2 = 1\\\\ 0.982 d^2 =1\\\\\nd\u00b2 = \\dfrac1{0.982}"
"d = \\sqrt{\\dfrac{1}{0.982}} = 1.009m"
Comments
Leave a comment