Question

A bar LM of weight (W) 80 N is hinged at L and is pulled by a cable attached at M by a force P, as shown in figure below.

Find the magnitude of force P (unit in N)?

Answer 1

$EF_y=0$

$0-P_x-\frac{1}{2}Wx=0$

$So -P_x- \frac{80}{2}x=0$

$-P_x=40x$

$-P= \frac{40x}{x}$

$P=40N$