A plate of a certain oil weighs 40kN. Calculate the specific mass, weight density and specific gravity of the oil.
Weight=40 kNVolume=5 m3Weight = 40\ kN\\ Volume = 5\ m³Weight=40 kNVolume=5 m3
ρ=40000/10 kg5 m3=800 kg/m3\rho = \dfrac{40000/10\ kg}{5\ m³}= 800\ kg/m³ρ=5 m340000/10 kg=800 kg/m3
(a) Specific mass;
γ=ρgγ=800×10=8000 N/m3\gamma=\rho g\\ \gamma = 800× 10 = 8000\ N/m³γ=ρgγ=800×10=8000 N/m3
(b) Weight density;
D=ρgD=800×10=8000 N/m3D=\rho g\\ D = 800× 10 = 8000\ N/m³D=ρgD=800×10=8000 N/m3
(c) Specific gravity;
SG=ρoilρH2O=8001000=0.8SG = \dfrac{\rho_{oil}}{\rho_{H_2O}}=\dfrac{800}{1000} = 0.8SG=ρH2Oρoil=1000800=0.8
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