Answer to Question #189947 in Mechanical Engineering for luke

Question

A cylindrical pipe with water flowing downward at 0.02 m3/s having top diameter of 0.08 m, bottom diameter of 0.04 m, and an elevation of 1.5 m. Determine the fluid pressure difference, kPa, across the pipe.

Answer 1

$velocity 1= 0.02/(\pi(0.08/2)^2)$

$v1= 1.018*10^-5m/s$

$velocity 2= 0.02/(\pi(0.08/2)^2)$

$v2= 2.546*10^-6m/s$

bernoulis equation = $1/2ev1^2 +p1+ egy1 = 1/2ev2^2 +p1+ egy1$

$p1-p2 = 0.5ev2^2+egy2 -0.5ev1^2$

$=0.5*997.77*(2.5-10^-6)^2+ 977.77*9.8*1.5-0.5*977.77*(1.018*10^-5)^2$

=$14667.219 N/m$

= 14.667kPa